File:Octaedro Estrellado De Abinader.gif
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Octaedro_Estrellado_De_Abinader.gif (478 × 282 pixels, file size: 2.27 MB, MIME type: image/gif, looped, 182 frames, 13 s)
Captions
Captions
The center of the 12 triangular faces of this polyhedron faithfully define the 12 intermediate vertices that form a truncated Archimedean hexahedron.
Summary
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Español: El octaedro estrellado de Luis Abinader es el dual del hexaedro truncado de Arquímedes.
El centro de las 12 caras triangulares de este poliedro definen fielmente los 12 vértices intermedios que forman un hexaedro truncado de Arquímedes. Este poliedro es conocido como la estrella octángula de Kepler y en el 2010 el profesor Jose Joel Leonardo demostró que este poliedro estrellado, es el poliedro estrellado conjugado del hexaedro truncado de Arquímedes. A esta demostración la bautizo con el nombre de octaedro estrellado de Luis Abinader en honor al presidente Abinader, dándola a conocer en diciembre del 2021. Si aplicamos la fórmula de Euler: C+V = A +2, C=12, V=8, A = 18, aplicando formula. 12 + 8 = 18 +2, 20 = 20. Claramente verificamos que se cumple la igualdad.
English: The stellated octahedron of Luis Abinader is the dual of the truncated hexahedron of Archimedes.
The center of the 12 triangular faces of this polyhedron faithfully define the 12 intermediate vertices that form a truncated Archimedean hexahedron. This polyhedron is known as Kepler's octagonal star and in 2010 Professor Jose Joel Leonardo showed that this star polyhedron is the conjugate star polyhedron of Archimedes' truncated hexahedron. I baptize this demonstration with the name of the stellated octahedron of Luis Abinader in honor of President Abinader, making it known in December 2021. If we apply Euler's formula: C + V = A +2, C = 12, V = 8 , A = 18, applying formula. 12 + 8 = 18 +2, 20 = 20. We clearly verify that the equality is true.
Français : L'octaèdre étoilé de Luis Abinader est le dual de l'hexaèdre tronqué d'Archimède.
Le centre des 12 faces triangulaires de ce polyèdre définit fidèlement les 12 sommets intermédiaires qui forment un hexaèdre d'Archimède tronqué. Ce polyèdre est connu sous le nom d'étoile octogonale de Kepler et en 2010, le professeur Jose Joel Leonardo a montré que ce polyèdre étoilé est le polyèdre étoilé conjugué de l'hexaèdre tronqué d'Archimède. Je baptise cette démonstration du nom de l'octaèdre étoilé de Luis Abinader en l'honneur du président Abinader, la faisant connaître en décembre 2021. Si on applique la formule d'Euler : C + V = A +2, C = 12, V = 8 , A = 18, en appliquant la formule. 12 + 8 = 18 +2, 20 = 20. On vérifie clairement que l'égalité est vraie. |
| Date | |
| Source | Own work |
| Author | Jose J. Leonard |
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 18:20, 16 December 2021 | | 478 × 282 (2.27 MB) | Jose J. Leonard (talk | contribs) | Uploaded own work with UploadWizard |
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