File:Gran Tetraedro Leonardiano Hueco.gif
Original file (932 × 510 pixels, file size: 1.75 MB, MIME type: image/gif, looped, 207 frames, 16 s)
Captions
Captions
Summary
[edit]
| Description |
Español: La quinta estelación del tetraedro está representada por el gran tetraedro Leonardiano hueco y el gran tetraedro Leonardiano ampliado, ambos poliedros fueron descubiertos por el investigador Dominicano Jose Joel Leonardo.
El gran tetraedro Leonardiano hueco está formado por 24 triángulos escaleno pitagórico (debido a que tiene sus tres lados desiguales y posee un ángulo recto, o ángulo de 90 grados) y por 12 triángulos isósceles de Jose (debido a que uno de los dos lados iguales, es menor que el lado desigual). El área del gran tetraedro Leonardiano hueco = Agtlh. Agtlh =10.012296 L elevado a potencia dos. El volumen del gran tetraedro Leonardiano hueco = Vgtlh El volumen del gran tetraedro Leonardiano hueco es igual al área del gran tetraedro Leonardiano hueco por el espesor que existe entre dos caras paralelas interiores, más el volumen del tetraedro regular imaginario que esta descrito por el conjunto de arista intermedias. Espesor = E. Vt = 0.117776 L3 Vgtlh=(Agtlh)(E)+ Vt =10.012296 L elevada a potencia 2(E) + 0.117776 L elevada a potencia 3. Vgtlh=10.012296 L elevada a potencia 2(E) + 0.117776 L elevada a potencia 3.English: The fifth tetralation of the tetrahedron is represented by the large hollow Leonardian tetrahedron and the large Leonardian expanded tetrahedron, both polyhedrons were discovered by the Dominican researcher Jose Joel Leonardo.
The large hollow Leonardian tetrahedron is made up of 24 Pythagorean scalene triangles (because it has its three unequal sides and has a right angle, or 90 degree angle) and 12 isosceles Jose's triangles (because one of the two equal sides) , is less than the uneven side). The area of the large hollow Leonardian tetrahedron = Agtlh. Agtlh = 10.012296 L raised to power two. The volume of the large hollow Leonardian tetrahedron = Vgtlh The volume of the large hollow Leonardian tetrahedron is equal to the area of the large hollow Leonardian tetrahedron by the thickness that exists between two internal parallel faces, plus the volume of the imaginary regular tetrahedron that is described by the set of intermediate edges. Thickness = E. Vt = 0.117776 L3 Vgtlh = (Agtlh) (E) + Vt = 10.012296 L elevated to power 2 (E) + 0.117776 L elevated to power 3. Vgtlh = 10.012296 L elevated to power 2 (E) + 0.117776 L elevated to power 3.Português: O quinto stellation do tetraedro é representado pelo grande tetraedro Leonardiano oco e do grande tetraedro expandiu Leonardiano, ambos os poliedros foram descobertos pelo pesquisador José Joel Leonardo.
A grande oco tetraedro Leonardiano consiste em 24 triângulos escaleno Pitágoras (porque tem três lados desiguais e com um ângulo recto, ou 90 graus) e 12 triângulos isósceles José (porque um dos dois lados iguais , é menor que o lado desigual). A área do grande tetraedro leonardiano oco = Agtlh. Agtlh = 10,012296 L elevado ao poder dois. O volume do grande tetraedro leonardiano oco = Vgtlh O volume de tetraedro Leonardiano grande lacuna é igual à área de grande tetraedro oco espessura Leonardiano entre duas faces paralelas interiores, mais o volume do tetraedro regular imaginário que é descrito pelo conjunto de borda intermédia. Espessura = E. Vt = 0,1117776 L3 Vgtlh = (Agtlh) (E) + Vt = 10,012296 L elevado na potência 2 (E) + 0,117776 L elevado na potência 3. Vgtlh = 10.012296 L elevado na potência 2 (E) + 0.117776 L elevado na potência 3.Français : La cinquième tétralation du tétraèdre est représentée par le grand tétraèdre Leonardian creux et le grand tétraèdre expansé Leonardian, ces deux polyèdres ont été découverts par le chercheur dominicain Jose Joel Leonardo.
Le grand tétraèdre Leonardien creux est composé de 24 triangles scalènes de Pythagore (car il a ses trois côtés inégaux et a un angle droit ou un angle de 90 degrés) et 12 triangles de Jose isocèle (parce que l'un des deux côtés égaux) , est moins que le côté inégal). La zone du grand tétraèdre Leonardian creux = Agtlh. Agtlh = 10.012296 L élevé pour alimenter deux. Le volume du grand tétraèdre Leonardian creux = Vgtlh Le volume du grand tétraèdre Leonardian creux est égal à la surface du grand tétraèdre Leonardian creux par l'épaisseur qui existe entre deux faces internes parallèles, plus le volume du tétraèdre régulier imaginaire décrit par l'ensemble des arêtes intermédiaires. Epaisseur = E. Vt = 0,117776 L3 Vgtlh = (Agtlh) (E) + Vt = 10,012296 L élevé à la puissance 2 (E) + 0,117776 élevé à la puissance 3. Vgtlh = 10.012296 élevé à la puissance 2 (E) + 0,117776 L élevé à la puissance 3. |
| Date | |
| Source | Own work |
| Author | Jose J. Leonard |
File:El_gran_tetraedro_Leonardiano_hueco.jpg
Licensing
[edit]
- You are free:
- to share – to copy, distribute and transmit the work
- to remix – to adapt the work
- Under the following conditions:
- attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
- share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original.
File history
Click on a date/time to view the file as it appeared at that time.
| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 02:11, 4 May 2019 | | 932 × 510 (1.75 MB) | Jose J. Leonard (talk | contribs) | User created page with UploadWizard |
You cannot overwrite this file.
File usage on Commons
There are no pages that use this file.
