File talk:Pn-junction-equilibrium-graph.svg

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There is an inaccuracy in the graphics. The E-field arrow direction does not correspond correctly to the E-field diagram. I suppose to invert the sign of the E value in the diagram. --109.226.165.251 10:30, 16 March 2015 (UTC)[reply]

The arrow and the diagram of the E-Field are correct.
The electric field is a vector field E and originates from positive and terminates at negative charges. Therefore, the arrow (direction of E) has the correct orientation. As a vector field the E-field can be split into E = E ex where E is the magnitude of the field at the point x and ex is the unit vector pointing in the direction of the x-axis. Because the x-axis is pointing in the opposite direction of E, the magnitude E (which is given in the diagram) must be negative. DerLangeJan (talk) 20:38, 11 August 2024 (UTC)[reply]

Direction of voltage ΔV

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I wonder if the direction of the arrow of the voltage ΔV across the space charge region is correct. From my point of view, the voltage should have the same direction as the E-field. DerLangeJan (talk) 22:58, 11 August 2024 (UTC)[reply]