File:The design of a hydro-electric plant at Ottawa, Illinois (1914) (14792801303).jpg

Identifier: designofhydroele00burn (find matches)
Title: The design of a hydro-electric plant at Ottawa, Illinois
Year: 1914 (1910s)
Authors: Burnett, William
Subjects: Hydroelectric power plants Theses
Publisher:
Contributing Library: University of Illinois Urbana-Champaign
Digitizing Sponsor: University of Illinois Urbana-Champaign

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ts that were used in calculations.Specific gravity of concrete r,?5 to^.5 ^Veight of concrete 140 to 150 pounds per cubic foot. Coefficient of friction between masonary and dry clajr ,510,Coefficient of friction betv/er;n rnasonary -■•n.^ -ret clay ,325, Calculations for the Center of Gravity,It will be necessary to divide the dam up into tvo sections. Thespillway is to be considered as one section and the piers of the spillv.raysthe other section. The? center of gravity is to be found grahpically. Get each section into an equivalent trapazoid. Then the centers ofthese two sections are found and the resultant of these two centers willgive th« center of gravity of the dam. By equivalent traonzoid is meant,one that will most nearly fit the outside dimensions of the section.Considering the spillway first; Given the figure ADEB, Draw lines con-necting DB and KA. Call the intersection of these two lines L,Now layoff on the line /lE the distance LE from A. Call this lenght AJ, Draw a o
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line from J to D,ancl bisect this line. Fron the bisection Q draw the lineto B. Then one third of this distance from Q to B will c^ve the centerof £:ravity of that section. Lines are drawn in the horizontal and thevertical planes from the two points that v/ere determined bjr the foregoingmethods. Draw medians of the triangle and the point where they intersectgives the true^ center of the dam. This only gives approximately resultsbut they are close enough to ansver th^ purpose, HesTilts, Considering the vertical side of the dam as the Y axis and thehorizontal side as the X axis, then t-:e center of gravity can be referedto as, X - 10.0 feet.Y=19,5 feet. This means that the center is located 10.^ feet from the Jrig- ■^.he ver-tical line and that the height afeove the base is 19,5 feet,. . Prom thisthe pressure of the water against the dam can be calculated and the restof the factors which determine the si^.e of the section can be obtained.The way in which the over turning moment is o

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