File:Dark Field Microscopy.gif
Original file (723 × 723 pixels, file size: 7.47 MB, MIME type: image/gif, looped, 70 frames, 7.0 s)
Captions
Summary
[edit]DescriptionDark Field Microscopy.gif |
English: If you illuminate a surface from the high refractive index side at a high enough angle, no light will be transmitted (total internal reflection). But if there is something on the surface, it will scatter light (that you can measure).
Small particles of low refractive index, will produce effectively spherical waves, which can thus be directly imaged against a very dark background. Plotting the modulus of the field instead of the intensity to make the effect more visible. The refractive indices are also unrealistically high, to make the visualization clearer. |
Date | |
Source | https://twitter.com/j_bertolotti/status/1410181128003231746 |
Author | Jacopo Bertolotti |
Permission (Reusing this file) |
https://twitter.com/j_bertolotti/status/1030470604418428929 |
Mathematica 12.0 code
[edit]\[Sigma] = 5.; \[Lambda]0 = 2.; k0 = N[(2 \[Pi])/\[Lambda]0];
\[Delta] = \[Lambda]0/20; \[CapitalDelta] = 40*\[Lambda]0;
\[Phi]in = Table[0, {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
dim = Dimensions[\[Phi]in][[1]];
d = \[Lambda]0/2; (*typical scale of the absorbing layer*)
Ren = Table[ If[y < 0, 3, 1], {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
Imn = Table[10 (E^-((x + \[CapitalDelta]/2)/d) + E^((x - \[CapitalDelta]/2)/d) + E^-((y + \[CapitalDelta]/2)/d) +E^((y - \[CapitalDelta]/2)/d)), {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
L = -1/\[Delta]^2*KirchhoffMatrix[GridGraph[{dim, dim}]]; (*Discretized Laplacian*)
n = Ren + I Imn;
M = L + DiagonalMatrix[ SparseArray[Flatten[n]^2 k0^2]]; (*Operator on the left-hand side of the equation we want to solve*)
sinstep[t_] := Sin[\[Pi]/2 t]^2;
sourcef[x_, y_, t_] := E^(-((x + (\[CapitalDelta]/4)*sinstep[t] )^2/(2 \[Sigma]^2))) E^(I 3.5*sinstep[t] x) E^(-((y + \[CapitalDelta]/2)^2/(2 (\[Lambda]0/2)^2))) E^(I k0 y);
frames1 = Table[
\[Phi]in = Table[Chop[sourcef[x, y, t] ], {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
b = -(Flatten[n]^2 - 1) k0^2 Flatten[\[Phi]in]; (*Right-hand side of the equation we want to solve*)
\[Phi]s = Partition[LinearSolve[M, b], dim]; (*Solve the linear system*)
ImageAdd[
ArrayPlot[ Transpose[((Abs[\[Phi]in + \[Phi]s])[[(4 d)/\[Delta] ;; (-4 d)/\[Delta], (4 d)/\[Delta] ;; (-4 d)/\[Delta]]]/Max[(Abs[\[Phi]in + \[Phi]s])[[(10 d)/\[Delta] ;; (-10 d)/\[Delta], (10 d)/\[Delta] ;; (-10 d)/\[Delta]]]])^1], ColorFunction -> "AvocadoColors" , DataReversed -> True, Frame -> False, PlotRange -> {0, 1}],
ArrayPlot[Transpose@Re[(n - 1)/50] , DataReversed -> True , ColorFunctionScaling -> False, ColorFunction -> GrayLevel, Frame -> False]
](*Plot everything*)
, {t, 0, 1, 1/(20 - 1)}];
stopstep[t_] := t^4;
frames2 = Table[
Ren1 = Ren + 10*RotateRight[DiskMatrix[3, dim], {0, 3 + Round[300*stopstep[t]]}];
n = Ren1 + I Imn;
M = L + DiagonalMatrix[SparseArray[Flatten[n]^2 k0^2]]; (*Operator on the left-hand side of the equation we want to solve*)
\[Phi]in = Table[Chop[sourcef[x, y, 1] ], {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
b = -(Flatten[n]^2 - 1) k0^2 Flatten[\[Phi]in]; (*Right-hand side of the equation we want to solve*)
\[Phi]s = Partition[LinearSolve[M, b], dim]; (*Solve the linear system*)
ImageAdd[
ArrayPlot[ Transpose[((Abs[\[Phi]in + \[Phi]s])[[(4 d)/\[Delta] ;; (-4 d)/\[Delta], (4 d)/\[Delta] ;; (-4 d)/\[Delta]]]/Max[(Abs[\[Phi]in + \[Phi]s])[[(10 d)/\[Delta] ;; (-10 d)/\[Delta], (10 d)/\[Delta] ;; (-10 d)/\[Delta]]]])^1], ColorFunction -> "AvocadoColors" , DataReversed -> True, Frame -> False, PlotRange -> {0, 1}],
ArrayPlot[Transpose@Re[(n - 1)/50] , DataReversed -> True , ColorFunctionScaling -> False, ColorFunction -> GrayLevel, Frame -> False]
](*Plot everything*)
, {t, 0, 1, 1/(40 - 1)}];
ListAnimate[Join[frames1(*,Table[frames1[[-1]],5]*), Reverse@frames2, Table[frames2[[1]], 10]] ]
Licensing
[edit]This file is made available under the Creative Commons CC0 1.0 Universal Public Domain Dedication. | |
The person who associated a work with this deed has dedicated the work to the public domain by waiving all of their rights to the work worldwide under copyright law, including all related and neighboring rights, to the extent allowed by law. You can copy, modify, distribute and perform the work, even for commercial purposes, all without asking permission.
http://creativecommons.org/publicdomain/zero/1.0/deed.enCC0Creative Commons Zero, Public Domain Dedicationfalsefalse |
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current | 08:36, 1 July 2021 | 723 × 723 (7.47 MB) | Berto (talk | contribs) | Uploaded own work with UploadWizard |
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