File:Cuboedro Triangular.jpg
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Español: Cuboedro triangular de Leonardo: Es un poliedro convexo que posee 72 caras triangulares irregulares uniformes(C=72), 108 aristas (A=108) y 38 vértices (V=38). Fue descubierto el 3 de enero del 2020 por el profesor José Joel Leonardo. El Cuboedro triangular de Leonardo es una estelación del Tetraquishexaedro o hexaedro tetrakis descubierto por el matemático Carles catalán en el siglo XIX.
Las formula de poliedro de Euler se cumple en este politopo tridimensional convexo, C+V-A=2, sustituyendo 72+38-108=110 -108=2. Además las fórmulas de sucesiones poliédricas triangulares también se cumplen en este poliedro triangular, C= 2L+2, V=L+3, A= 3L+3, despejando la variable (L) en (V) y sustituyendo. L= V-3 = 38 -3= 35, L=35. C=2L+2= 2(35)+2=70+2=72, C=72. A= 3L+3= 3(35)+3= 105+3= 108, A=108English: Leonardo's triangular cubohedron: It is a convex polyhedron that has 72 uniform irregular triangular faces (C = 72), 108 edges (A = 108) and 38 vertices (V = 38). It was discovered on January 3, 2020 by Professor José Joel Leonardo. Leonardo's triangular cubohedron is a stellation of the Tetraquishexahedron or tetrakis hexahedron discovered by the mathematician Carles Catalan in the 19th century.
Euler's polyhedron formula is fulfilled in this three-dimensional convex polytope, C + V-A = 2, substituting 72 + 38-108 = 110-108 = 2. In addition the formulas of triangular polyhedral sequences are also fulfilled in this triangular polyhedron, C = 2L + 2, V = L + 3, A = 3L + 3, clearing the variable (L) in (V) and substituting. L = V-3 = 38 -3 = 35, L = 35. C = 2L + 2 = 2 (35) + 2 = 70 + 2 = 72, C = 72. A = 3L + 3 = 3 (35) + 3 = 105 + 3 = 108, A = 108Français : Cuboèdre triangulaire de Leonardo : C'est un polyèdre convexe qui a 72 faces triangulaires irrégulières uniformes (C = 72), 108 arêtes (A = 108) et 38 sommets (V = 38). Il a été découvert le 3 janvier 2020 par le professeur José Joel Leonardo. Le cuboèdre triangulaire de Léonard est une stellation du tétraquishexaèdre ou hexaèdre tétrakis découvert par le mathématicien catalan Carles au XIXe siècle.
La formule du polyèdre d'Euler est remplie dans ce polytope convexe tridimensionnel, C + V-A = 2, en remplaçant 72 + 38-108 = 110-108 = 2. De plus, les formules de séquence polyédrique triangulaire sont également respectées dans ce polyèdre triangulaire, C = 2L + 2, V = L + 3, A = 3L + 3, effaçant la variable (L) dans (V) et remplaçant. L = V-3 = 38 -3 = 35, L = 35. C = 2L + 2 = 2 (35) + 2 = 70 + 2 = 72, C = 72. A = 3L + 3 = 3 (35) + 3 = 105 + 3 = 108, A = 108 |
| Date | |
| Source | Own work |
| Author | Jose J. Leonard |
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| current | 18:23, 3 January 2020 | | 6,120 × 3,600 (1.17 MB) | Jose J. Leonard (talk | contribs) | User created page with UploadWizard |
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